Question

​What is the equation of a line with a slope of ​ ​ −4 ​ ​ and a point ​ (−2, 5) ​ on the line?

Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.



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Answer 1

Answer:

y = -4x + 13

Step-by-step explanation:

m = -4, (-2, 5)

you're going to put this into point-slope form, which is y - y1 = m (x - x1).

y - 5 = -4 (x - (-2))

distribute the -4 (and the two negatives make a positive)

y - 5 = -4x + 8

add five on both sides to get y on its own, on the left, adding 5 to the five cancels out five.

and you get:

y = -4x + 13

Answer 2

Expressing the equation in the form y = mx + b where m is slope and b is y-

intercept is represented as y = -4x - 3

The slope intercept form is represented as follows:

y = mx + b

where

m = slope

b = y-intercept

Therefore,

m = -4

using the coordinate (-2, 5) lets find b

y = -4x + b

5 = -4(-2) + b

5 = 8 + b

b = 5 - 8

b = -3

Therefore,

y = -4x - 3

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