Match the following reasons with the statement givem
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Answer:
AAS(Angle-Angle-Side) postulate states that if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then the two triangles are congruent
In triangle RAS and triangle QAT
[tex]\angle R =\angle Q[/tex] [Angle]
[tex]AS =AT[/tex] [Side] [Given]
By Base Angle Theorem states that in an isosceles triangle(i.e, AST), the angles opposite the congruent sides(AS =AT) are congruent.
⇒ [tex]\angle 5= \angle 6[/tex] [By base ∠'s of isosceles triangle are equal]
By definition of supplementary angles, if two Angles are Supplementary when they add up to 180 degrees.
[tex]\angle 4[/tex], [tex]\angle 5[/tex] are supplementary and [tex]\angle 6[/tex], [tex]\angle 7[/tex] are supplementary.
⇒[tex]\angle 4+ \angle 5 =180^{\circ}[/tex] and
[tex]\angle 6+ \angle 7 =180^{\circ}[/tex]
Two [tex]\angle 's[/tex] supplementary to equal [tex]\angle 's[/tex]
[tex]\angle 4+ \angle 5 =\angle 6+ \angle 7[/tex]
Since, [tex]\angle 5 =\angle 6[/tex]
then, we get;
[tex]\angle 4 =\angle 7[/tex] [Angle]
then, by AAS postulates,
[tex]\triangle RAS \cong \triangle QAT[/tex]
By CPCT[Corresponding Part of Congruent Triangles are equal]
[tex]RS = QT[/tex] Hence Proved!