Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
[tex]\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right][/tex]
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
[tex]\left[\begin{array}{ccc}1&5\\1&7\end{array}\right] [/tex]
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2