Question

Can you please solve this question with procedure, please????

. h (x) = 6x^2+ 3x + 1

Answer 1

Answer:

Step-by-step explanation:

H

$6x^2+3x+1=0\\a=6,b=3,c=1\\(-b+-\sqrt{b^2-4ac} )/2a\\\\\frac{-3+-\sqrt{-15} }{12}$

The roots are:

$\frac{-3+-i\sqrt{15} }{12}$