Answer :
Part 1 : conversion factor required for 30%(m/m) NaCl solution.
30%(m/m) NaCl solution that means 30 grams of NaCl is present in 100 gram of solution.
Conversion factor : [tex]30\%\text{ of NaCl solution}=\frac{30\text{ g of NaCl}}{100\text{ g of solution}}[/tex]
Part 2 : conversion factor required for 8%(v/v) ethanol solution.
8%(v/v) ethanol solution that means 8 ml of ethanol is present in 100 ml of solution.
Conversion factor : [tex]8\%\text{ of ethanol solution}=\frac{8\text{ ml of ethanol}}{100\text{ ml of solution}}[/tex]
Part 3 : conversion factor required for 14%(m/v) fructose solution.
14%(m/v) fructose solution that means 14 grams of fructose is present in 100 ml of solution.
Conversion factor : [tex]14\%\text{ of fructose solution}=\frac{14\text{ g of fructose}}{100\text{ ml of solution}}[/tex]
Part 4 : conversion factor required for 5.0 M HBr solution.
'M' represent the 'molarity' which is defined as the number of moles of solute present in one liter of solution.
5.0 M HBr solution that means 5 moles of HBr is present in 1 liter of solution.
Conversion factor : [tex]5.0M\text{ HBr solution}=\frac{5\text{ moles of HBr}}{1\text{ L of solution}}[/tex]
