Respuesta :

Answer:

0


Step-by-step explanation:

[tex]g(x) = 3x + 1 \\\ y = 3x + 1[/tex]


Changing x to y and y to x:


[tex]x = 3y + 1 \\\ 3y = x - 1 \\\ y = \frac{x - 1}{3} \\\ g^{-1}(x) = \frac{x - 1}{3} \\\ g^{- 1} (1) = \frac{1 - 1}{3} \\\ g^{- 1} (1) = 0[/tex]


I hope I helped you.

Answer:

0

Step-by-step explanation:

Hope this helps.

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