Can you help me graph this equation?
![Can you help me graph this equation class=](https://us-static.z-dn.net/files/d00/6e2027cb3d3d30b2e242893890b61868.png)
A graph is attached
The equation is in slope-intercept form:
... y = mx + b
Here, the value of m (the slope) is 1/2, and the value of b (the y-intercept) is -3.
This means that point (0, -3) is a point on the graph. This point is on the y-axis, 3 units below the x-axis.
Slope is sometimes referred to as "rise over run." The slope of 1/2 means the line will rise 1 unit for each 2 units to the right. That is, for some point (x, y) on the ine, another point will be found at (x+2, y+1).
Given a point at (0, -3), another point will be (0, -3) +(2, 1) = (2, -2), and another point will be (2, -2) +(2, 1) = (4, -1).
You can plot as many points as you like, then draw the line through them.