Given that,
mass of ball , m =11 lbs
Time , t = 1.0 seconds
Acceleration , a = 9.8 m/s²
Distance , s = ?
Since, we know that,
S = Vi *t + 1/2 at²
Since initial velocity is zero in this case (ball was at state of rest before falling to the ground)
S = 1/2 *9.8 * (1)²
S = 4.9 m
The distance covered by ball after one second will be 4.9 m.