I could really use some help with these 4 problems. Any help will be greatly appreciated!
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(7) is the same problem with different numbers as (4) in another question you posted: https://brainly.com/question/11799042
(8) is not correct. [tex]\mathbf u\cdot\mathbf v=(12)(-15)+(4)(-5)=-200[/tex]
(9) is not correct. The direction of the vector [tex]\langle3,4\rangle[/tex] is [tex]\theta[/tex] where
[tex]\tan\theta=\dfrac34\implies\theta=\tan^{-1}\dfrac34[/tex]
so the applied force is the vector
[tex]\mathbf F=\langle14\cos\theta,14\sin\theta\rangle=\langle11.2,8.4\rangle[/tex]
(if you're not sure how to compute the (co)sine of the inverse-tangent expression, note that a tangent of 3/4 corresponds to a right triangle with hypotenuse 5)
The object is moved 7 ft in the same direction as [tex]\mathbf F[/tex], so that its displacement is given by the vector
[tex]\mathbf d=\langle7\cos\theta,7\sin\theta\rangle=\langle5.6,4.2\rangle[/tex]
Then the work done on the object is the dot product of these two vectors,
[tex]W=\mathbf F\cdot\mathbf d=(11.2)(5.6)+(8.4)(4.2)=98\approx97[/tex]
(the discrepancy here might be coming from finding a numerical value for [tex]\theta[/tex])
(10) is correct. We can find a unit vector pointing in the direction of any vector [tex]\mathbf v[/tex] by dividing [tex]\mathbf v[/tex] by its magnitude:
[tex]\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\frac23\,\mathbf i-\frac12\,\mathbf j}{\sqrt{\left(\frac23\right)^2+\left(-\frac12\right)^2}}=\dfrac45\,\mathbf i-\dfrac35\,\mathbf j[/tex]