Respuesta :

Answer:

Answer (a):

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Answer (b)

9 large dogs.

Step-by-step explanation:

Paws at Play made a total of $1234 grooming 22 dogs.

Paws at Play charges $43 to groom each small dog and;

$75 for each large dog.

Let the number of small dogs be 's'

And the number of large dogs be 'l'

A system of equations will be:

s + l = 22 ... (i)

43s + 75l = 1234 ... (ii)

Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;

43s + 43l = 946 ... (i)

43s + 75l = 1234 ... (ii)

Subtracting (i) from (ii) we get;

32l = 288 , l = [tex]\frac{288}{32}[/tex] = 9

So there are 9 large dogs.

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