Question

A student measured the specific heat of water to be 4.89 J/g · °C. The literature value of the specific heat of water is 4.18 J/g · °C. What was the student's percent error? %

Answer 1

4.89-4.18/4.18x100 = 0.71/4.18x100~1/6x100~16.7%

Answer 2

Answer:

16.98%

Explanation:

Given:

True value of specific heat of water = 4.18 J/g°C

Measured value of specific heat of water = 4.89 J/g°C

Percentage error can be calculated as follows:

$error\% = \frac{|\text{True value-measured value}|}{\text{True value}}\times 100\% \\ e = \frac{|4.18-4.89|}{4.18}\times 100\% = 16.98\%$