Question

what are the zeros of the polynomial functio ? f(x)=x^3+x^2-9x-9

Answer 1

Answer:

x = - 1

x1 = - 3

x2 = 3

Step-by-step explanation:

x^2(x + 1) - 9(x + 1)    = f(x)                  x + 1 is a common factor

(x + 1) [ x^2 - 9]          = f(x)                 factor x^2 - 9

(x + 1)(x - 3)(x + 3)

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x + 1 = 0

x = - 1

x - 3 = 0

x = 3

x + 3 = 0

x = - 3

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Answer

x = - 1

x1 = - 3

x2 = 3