Answer:
[tex](x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)[/tex]
Step-by-step explanation:
Given that f(x) is a polynomial function.
This implies that f(x) has x terms of positive integral degrees and also rational coefficients only.
Since an irrational root is given a root of f(x), we find that its conjugate also should be a root of f(x)
i.e. If [tex]-2+\sqrt{8}[/tex] is a root, then [tex]-2-\sqrt{8}[/tex] is also a root.
(Because this only when multiplied will make coefficients rational)
So the factors of f(x) should be atleast
[tex](x+2-\sqrt{9}) , (x-2+\sqrt{9}) ,(x-9)[/tex]
There can be other factors also but this is compulsory