Question

The silver isotope with 60 neutrons. Enter the chemical symbol of the isotope.

Answer 1

Ag with a superscript of 107 and a subscript of 47

Answer 2

The silver (Ag) isotope with 60 neutrons has the chemical symbol: $^{107}_{47}X$.  

Any isotope can be represented as follows:

$^{A}_{Z}X$

Where:

Z: is the atomic number = number of protons

A: is the mass number

The atomic number of Silver is 47, so:

$^{A}_{47}X$

Now, we need to find the mass number:

$A = Z + n$

Where:

n: is the number of neutrons = 60

$A = Z + n = 47 + 60 = 107$

Therefore, the chemical symbol of Ag-47 is $^{107}_{47}X$.  

You can find more about isotopes here:

• https://brainly.com/question/11394246?referrer=searchResults

• https://brainly.com/question/11249809?referrer=searchResults

I hope it helps you!