Answer: The first box would have the value 504, while the second box has the value 84
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Work Shown:
nPr = (n!)/(n-r)!
9P3 = (9!)/(9-3)!
9P3 = (9*8*7*6!)/(6!)
9P3 = 9*8*7
9P3 = 504
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nCr = (nPr)/(r!)
9C3 = (9P3)/(3!)
9C3 = (504)/(3*2*1)
9C3 = 504/6
9C3 = 84
note: you can also use the formula nCr = (n!)/(r!*(n-r)!) to compute the combination value, which as you can probably notice, it has the nPr formula buried in it. This is what connects the two concepts of nPr and nCr. The exclamation mark means factorial.
