HW #35: similar polygons
![HW 35 similar polygons class=](https://us-static.z-dn.net/files/d93/95d9fb16d68b0324cfb0fa92c4a0b097.png)
Answer:
Q 9:
Because the two polygons are similar so AB ≈ PQ = SR
Scale factor is 25/20 = 1.25
Perimeter of ABCD = 14+20+14+20 = 68
We can find the length of SP by multiplying the scale factor with the AD so
SP = 14 * 1.24= 17.5
Perimeter of PQRS = 17.5+25+17.5+25 = 85
-----------------------------------------------------------------------------------
Q 10:
Because the two polygons are similar so AD ≈. EH
Scale factor is 7/14 = 0.5
Perimeter of ABCD = 12+14+13+26 = 65
Because the two polygons are similar so DC ≈ HG
and our scale factor is 0.5 so HG = 13/2 = 6.5
Perimeter of EFHG = 6 + 7 + 6.5 + 13 = 32.5
----------------------------------------------------------------------------------
Q 11:
The Geometric Mean is a special type of average where we multiply the numbers together and then take a square root (for two numbers). And the formula for finding the Geometric mean of two numbers a and b is
[tex]\sqrt{a*b}[/tex]
So geometric mean of the 8 and 10 can be found as
[tex]\sqrt{8*2} = \sqrt{16} = 4[/tex]
-----------------------------------------------------------------------------------
Q 12:
Similarly we can using the above formula of finding the geometric mean of 5 and 45 as
[tex]\sqrt{5*45} = \sqrt{225} = 15[/tex]
-------------------------------------------------------------------------------
Q 13:
and we can find the geometric mean of 6 and 30 by using the same formula
[tex]\sqrt{6*30} = \sqrt{180} = 13.41[/tex]