Question

what is the equation of a line that passes through the point (6,1) and perpendicular to the line whose equation is 2x+y= - 6 ?

Answer 1

Answer:

y = $\frac{1}{2}$ x - 2

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

rearrange 2x + y = - 6 into this form

subtract 2x from both sides

y = - 2x - 6 ← in slope-intercept form

with slope m = - 2

given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{-2}$ = $\frac{1}{2}$

y = $\frac{1}{2}$ x + c ← is the partial equation

to find c substitute (6, 1) into the partial equation

1 = 3 + c ⇒ c = 1 - 3 = - 2

y = $\frac{1}{2}$ x - 2 ← equation of perpendicular line