Question

∆ABC is transformed with the center of dilation at the origin.

Pre-image: ∆ABC with vertices A(−5, −4), B(−7, 3), C(3, −2)
Image: ∆A'B'C' with vertices A' (−3.75, −3), B' (−5.25, 2.25), C' (2.25, −1.5)
What is the scale factor of the dilation that maps the pre-image to the image?

Answer 1

Answer:

3/4

Step-by-step explanation:

We are to find the scale factor of the dilation that maps the pre-image of triangle ABC with vertices A(−5, −4), B(−7, 3) and C(3, −2) to the image triangle A'B'C' with vertices A' (−3.75, −3), B' (−5.25, 2.25) and C' (2.25, −1.5).

Center of dilation is at the origin.

To find the scale factor, we will divide the corresponding vertices of the image and pre-image.

A(−5, −4) ---> A' (−3.75, −3) = $\frac{-3.75}{-5} , \frac{-3}{-4}=(\frac{3}{4} , \frac{3}{4})$

B(−7, 3) ---> B' (−5.25, 2.25) = $\frac{-5.25}{-7} , \frac{2.25}{3}=(\frac{3}{4} , \frac{3}{4})$

C(3, −2) ---> C' (2.25, −1.5) = $\frac{2.25}{3} , \frac{-1.5}{-2}=(\frac{3}{4} , \frac{3}{4})$

Therefore, the scale factor of the dilation is 3/4.