Question

∆ABC is transformed with the center of dilation at the origin.

Pre-image: ∆ABC with vertices A(2, 5), B(6, 10), C(9, −1)
Image: ∆A'B'C' with vertices A' (0.5, 1.25), B' (1.5, 2.5), C' (2.25, −0.25)
What is the scale factor of the dilation that maps the pre-image to the image?

Answer 1

Answer:

1/4

Step-by-step explanation:

We are to find the scale factor of the dilation that maps the pre-image of triangle ABC with vertices A(2, 5), B(6, 10) and C(9, −1) to the image triangle A'B'C' with vertices A' (0.5, 1.25), B' (1.5, 2.5), C' (2.25, −0.25).

Center of dilation is at the origin.

To find the scale factor, we will divide the corresponding vertices of the image and pre-image.

A(2, 5) ---> A' (0.5, 1.25) = $\frac{0.5}{2} , \frac{1.25}{5}=(\frac{1}{4} , \frac{1}{4})$

B(6, 10) ---> B' (1.5, 2.5) = $\frac{1.5}{6} , \frac{2.5}{10}=(\frac{1}{4} , \frac{1}{4})$

C(9, −1) ---> C' (2.25, −0.25) = $\frac{2.25}{9} , \frac{-0.25}{-1}=(\frac{1}{4} , \frac{1}{4})$

Therefore, the scale factor of the dilation is 1/4.