Question 11 options:
m∥n, m∠1 = 65°, m∠2 = 60°, and m∠6 = 85°. What is m∠DBC?
![Question 11 options mn m1 65 m2 60 and m6 85 What is mDBC class=](https://us-static.z-dn.net/files/d10/0b11ca32376650fb57f90ca611000265.jpg)
Answer:
∠DBC = 40°
Step-by-step explanation:
∠5 = ∠3 + ∠4 = 180° - ∠6 . . . . relationship of angles at a transversal, vertical angles
∠3 = 180° - ∠1 - ∠2 . . . . . . sum of angles of a triangle
Then
∠4 = 180° - ∠6 - (180° - ∠1 - ∠2) = ∠1 +∠2 -∠6 . . . . substitute for ∠3
∠4 = 65° +60° -85° = 40°
∠4 = ∠DBC = 40°