Respuesta :

When an exponent is negative, you move it to the other side of the fraction to make the exponent positive.

For example:

[tex]x^{-2}[/tex] or [tex]\frac{x^{-2}}{1} =\frac{1}{x^2}[/tex]

[tex]\frac{1}{y^{-3}} =\frac{y^3}{1}[/tex] or y³



f(-2) This means that x is -2, so you can plug in -2 for "x" in the equation

[tex]f(x)=3^x[/tex]

[tex]f(-2)=3^{-2}[/tex]

[tex]f(-2)=\frac{1}{3^2}[/tex]

[tex]f(-2)=\frac{1}{9}[/tex]


Your answer is D

The value of the function f(-2) will be 1/9

What is a function?

A mathematical relationship from a set of inputs to a set of outputs is called a function.

How to find the value of f(-2) ?

The given function is f(x) = [tex]3^{x}[/tex]

  • To find f(-2) , we will have to put -2 in place of x

∴ f(-2) will be = [tex]3^{-2}[/tex]

  • Now, we know that [tex]a^{-b}[/tex] can be written as  [tex]\frac{1}{a^{b} }[/tex]

So,  [tex]3^{-2}[/tex] will be equal to 1/9

∴ The value of f(-2) will be 1/9

Option D is correct.

Find more about "Functions" here: brainly.com/question/4025726

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