Answer Number 2 Already Did Part 1
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Solve for y (this means you need to isolate/get y by itself)
-2x + 5 > -6x + 15 - 3y Add 6x on both sides
4x + 5 > 15 - 3y Subtract 15 on both sides
4x - 10 > -3y Divide -3 on both sides (when you multiply or divide a negative number on both sides, you flip the inequality sign)
[tex]-\frac{4}{3}x+\frac{10}{3} <y[/tex]
To determine if (0,0) is a solution, plug it into the inequality.
[tex]-\frac{4}{3}x+\frac{10}{3} <y[/tex]
[tex]-\frac{4}{3}(0)+\frac{10}{3}<0[/tex]
[tex]\frac{10}{3} <0[/tex]
This is not a solution because 10/3 is not less than 0