A, and here's how you do it:
First, just disregard the bottom half of the fraction, and focus on the top part. So on the top, you first multiply the bottom and the top of the first fraction by two, so you get:
[tex] \frac{2x}{8} + \frac{1}{8} [/tex]
Then write all numerators above the common denominator so you get:
[tex] \frac{2x + 1}{8} [/tex]
Then you can add the bottom part of the fraction back so you can have:
2x + 1
—
8
———
x²
—
4
Then multiply it by the formula:
a
—
b. a x d
— = —
c. b x c
—
d
Then you'll get:
[tex] \frac{(2x + 1) \times 4}{8 {x}^{2} } [/tex]
Then reduce it by 4, so you'll get A. as your answer.