Question

$\frac{1}{4} + \frac{1}{4} + x - \frac{3}{4}$

Answer 1

$\dfrac{1}{4}+\dfrac{1}{4}+x-\dfrac{3}{4}=\left(\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{3}{4}\right)+x=\dfrac{1+1-3}{4}+x=\dfrac{-1}{4}+x=x-\dfrac{1}{4}$