Answer:
−1 + i times the square root of 3
is the answer.
Step-by-step explanation:
Given is a quadratic equation in x
[tex]x^2+2x+4\\= x^2+2x+1+3\\=(x+1)^2+3[/tex]
using completion of squares method
Equate to 0
[tex](x+1)^2+3 =0\\(x+1)^2 = -3\\[/tex]
Take square root
[tex](x+1) = \sqrt{-3} =±i\sqrt{3}[/tex]
Subtract one from both sides
x = [/tex]-1±i\sqrt{3}[/tex]
The last option namely
−1 + i times the square root of 3 only matches with our answre
Hence last option is right.