What is the equation of a line that passes through the point (1, 8) and is perpendicular to the line whose equation is y=x/2+3 ?

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Answer:

The equation of the line would be y = -2x + 10

Step-by-step explanation:

In order to find the equation of this line, we first have to note that perpendicular lines have opposite and reciprocal slopes. Therefore, since the original line has a slope of 1/2, we know the new line will have a slope of -2. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 8 = -2(x - 1)

y - 8 = -2x + 2

y = -2x + 10

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