Question

The sum of three consecutive odd numbers is 63. What is the smallest of these numbers?

Answer 1

Answer: The smallest number = 19

Step-by-step explanation:

We'll call X the smallest of those odd numbers

Then x + (x+2) + (x+4) = 63

X + X + 2 + X + 4 = 63

3X + 6 = 63

3X = 63 - 6 = 57

X = 57/3 = 19

The three consecutives odd numbers are 19, 21, 23

The sum = 19+21+23 = 63

Your answer : The smallest number = 19

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