Question

in what direction is there a net force of 200?
A. Left
B.right
C.up
D. Down

Answer 1

Answer: B. Right

Explanation:

According to this Free Body Diagram we have:

$\sum F_{y}=300 N - 300 N = 0 N$

$\sum F_{x}=-200 N + 400 N = 200 N$ (being the left negative and the right positive)

So, since the magnitude of the net force is positive its direction is to the right.

Answer 2

Answer:

right

Explanation:

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