[tex]\dfrac{3}{10}y-\dfrac{2}{5}=\dfrac{1\cdot3}{5\cdot2}y-\dfrac{1\cdot2}{5\cdot1}=\dfrac{1}{5}\left(\dfrac{3}{2}y-2\right)\\\\\\1.1x+9.9=1.1\cdot x+1.1\cdot9=1.1(x+9)[/tex]
