Write a recursive formula for the sequence

Answer:
Option B: a1= 15 , [tex]a_n = 2a_{n-1}- 4[/tex]
Step-by-step explanation:
Given sequence is 15, 26, 48, 92, 180..........
First term is a1, so a1= 15
To get second term 26, we multiply the first term with 2
So it becomes 15*2 = 30
Then we subtract 4 from 30. so 30-4=26
To get third term 48,
previous term 26 *2 - 4= 52-4=48
a_n is the first term and a_(n-1) is the previous term
To get recursive formula
multiply the previous term by 2 and then subtract 4
So recursive formula becomes
[tex]a_n = 2a_{n-1}- 4[/tex]
Option B is correct