Answer:
Yes
Step-by-step explanation:
Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.
The solution may vary like Integers, rationals, irrationals or complex solutions.
To find two roots of the equation we can always use the formula given below to solve a quadratic equation,
For the quadratic equation,
[tex]ax^2+bx+c=0[/tex], we have,
[tex]x= \frac{-b\pm \sqrt{b^2-4 ac}}{2a}[/tex]
If the discriminant is greater than [tex]b^2[/tex], we get complex roots.
