Question

What is the standard form of the equation of the parabola shown in the graph?

Answer 1

Answer:  $x^2=-16y$

Step-by-step explanation:

Since, the standard form of a parabola which is along to the y-axis,

$y=a(x-h)^2+k^2$

Where (h,k) is the vertex of the parabola,

By the given diagram,

The vertex of the parabola along to the y-axis = (0,0)

⇒ h = 0, k=0

By substituting these values in the above equation,

We get,

$y=a(x-0)^2+0$

$\implies y = ax^2$   --------(1)

Now, again by the given diagram the parabola is passing through the point (-4,-1),

⇒ This point will be satisfy the equation of parabola,

⇒ $-1 = a(-4)^2$

⇒ $-1 = 16a$

⇒ $\frac{-1}{16}=a$

By substituting this value in equation (1),

We get,

$y=\frac{-1}{16}x^2$

$\implies -16 y = x^2$

Which is the required equation of the given parabola.

⇒ First option is correct.

Answer 2

Answer:

answer is A on edge

Step-by-step explanation: