Answer:
We are given the probability of students choosing the left lunch line at school is [tex]p=0.431[/tex]
We have to find the variance of the binomial distribution of 982 students choosing the left lunch line today.
Therefore, n = 982
We know that the variance of Binomial distribution is:
[tex]Variance = n \times p \times (1-p)[/tex]
[tex]=982 \times 0.431 \times (1-0.431)[/tex]
[tex]=240.82[/tex] rounded to 2 decimal places
Therefore, the variance of the binomial distribution of 982 students choosing the left lunch line today is 240.82
