Answer: The net ionic equation for the cobalt-silver voltaic cell is [tex]Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)[/tex]
Explanation: In cobalt-silver voltaic cell, one half of the cell consists of cobalt electrode immersed in [tex]Co(NO_3)_3[/tex] solution ( which means that [tex]Co^{3+}[/tex] are present in the solution) and other half of the cell consists of the Ag electrode immersed in [tex]AgNO_3[/tex] solution ( which means that [tex]Ag^+[/tex] is present in the solution)
The two electrodes are joined by the copper wire. The cobalt electrode acts as an anode and the silver electrode acts a cathode.
At anode, oxidation reaction takes place and at cathode, reduction reaction takes place.
At Anode : [tex]Co(s)\rightarrow Co^{3+}(aq.)+3e^-[/tex]
At Cathode: [tex][Ag^+(aq.)+e^-\rightarrow Ag(s)]\times 3[/tex]
Net ionic equation: [tex]Co(s)+3Ag^+(aq.)\rightarrow Co^{3+}(aq.)+3Ag(s)[/tex]