Question

Ali graphs the function f(x) = –(x + 2)2 – 1 as shown. Which best describes the error in the graph?
The axis of symmetry should be x = –1.
The axis of symmetry should be x = 2.
The vertex should be a maximum.
The vertex should be (–2, 1).

Answer 1

Answer:

the vertex should be a maximum

Step-by-step explanation:

given y = - (x + 2)² - 1

compare to equation in vertex form

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

⇒ vertex = (- 2, - 1) ← correct

the axis of symmetry passes through the vertex , is vertical with equation

x = - 2 ← correct

• If a > 0, then vertex is a minimum

• If a < 0, then vertex is a maximum

here a < 0 ⇒ vertex should be a maximum

Answer 2

The axis of symmetry should be x=2 describe error in the graph.

We have given that the function y = - (x + 2)² - 1

What is the vertex form of the equation?

$y = a(x - h)^2 + k$

Where (h, k) are the coordinates of the vertex and a is a multiplier

compare to given  equation with  vertex form.

so we have a=-1,

-h=2 implies that h=-2

k=-1

Therefore the vertex is (h,k)=(-2,-1)

vertex = (- 2, - 1)  

In the given graph the axis of symmetry passes through the vertex , is vertical with equation

x = - 2 is correct.

When the a > 0, vertex is a minimum

when  a < 0, implies that vertex is a maximum

here a=-1 < 0 implies vertex should be a maximum

Since, the vertex(-2,-1) is maximum

Therefore the axis of symmetry should be x=2 describe error in the graph

To learn more about the maximum vertex visit:

https://brainly.com/question/12446886