Respuesta :
The Second Derivative Test asserts that
- f'(c) = 0 and f''(c) > 0 implies that f has a local minimum at c
- f'(c) = 0 and f''(c) < 0 implies that f has a local maximum at c.
Intuitively, f''(c) > 0 means a smiley face so any critical number of f where f'(c) = 0 should result in a local minimum, the local bottom extreme of the happy face. f''(c) < 0 means a frowning face so any critical number of f where f'(c) = 0 should result in a local maximum, the local top extreme of the happy face
It is inconclusive when f''(c) = 0 or f''(c) does not exist. (For example, consider [tex]f(x) = x^3[/tex]. It has no local maxima or minima, yet [tex]f'(0) = 0[/tex] and [tex]f''(0) = 0[/tex].)
Therefore,
- From f’(3) = 0 and f’’(3) = -2, we can conclude that f has a local maximum at 3.
- From f’(-2) = 0 and f’’(-2) = 2, we can conclude that f has a local minimum at -2.
- From f'(4) = 0 and f''(4) = 0, we cannot conclude anything from just those two pieces alone. We cannot determine if f has a local maximum or minimum at 4, nor can we say anything about inflection points since we do not know if f'' changes sign at x = 4.
Answer:
Step-by-step explanation:
- There is a local maximum at 3 sice the derivative is null and f"(3)≤0
- There is a local minimum since f'(-2)=0 and f"(-2)≤0
- 4 here could be inflection point since f"(4)=0
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