Question

Rewrite 0.37 in expanded form using powers of ten.
A) (3 × 1) + (7 × 10)
B) (3 × 10) + (7 × 100)
C) (3 ×
1
10
) + (7 ×
1
100
)
D) (3 ×
1
100
) + (7 ×
1
1000
)

Answer 1

$0.37=0.3+0.07=\dfrac{3}{10}+\dfrac{7}{100}=\left(3\times\dfrac{1}{10}\right)+\left(7\times\dfrac{1}{100}\right)\to\boxed{C.}$