At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate of 41.42% every year. The function below models the population of chameleons in the zoo, where x represents the number of years since the chameleons were introduced into the zoo.
A. The average rate of change in the population between year 4 and year 6 was 41 more than the average rate of change in the population between year 6 and year 8.
B. The average rate of change in the population between year 2 and year 4 was approximately half the average rate of change in the population between year 4 and year 6. C. The average rate of change in the population between year 4 and year 6 was the same as the average rate of change in the population between year 6 and year 8. D. The average rate of change in the population between year 2 and year 4 was approximately double the average rate of change in the population between year 4 and year 6.

Respuesta :

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, [tex]P_0=15[/tex]

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

[tex]P(x)=P_0(1+r)^x[/tex]

now, we can plug values

[tex]P(x)=15(1+0.4142)^x[/tex]

[tex]P(x)=15(1.4142)^x[/tex]

Average rate of change between 2 years and 4 years:

we can use formula

[tex]A_1=\frac{P(4)-P(2)}{4-2}[/tex]

now, we can plug values

[tex]A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}[/tex]

[tex]A_1=14.99914[/tex]

Average rate of change between 4 years and 6 years:

we can use formula

[tex]A_2=\frac{P(6)-P(4)}{6-4}[/tex]

now, we can plug values

[tex]A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}[/tex]

[tex]A_2=29.99770[/tex]

Average rate of change between 6 years and 8 years:

we can use formula

[tex]A_3=\frac{P(8)-P(6)}{8-6}[/tex]

now, we can plug values

[tex]A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}[/tex]

[tex]A_3=59.99425[/tex]

now, we will check each options

option-A:

we can see that

[tex]A_3-A_2=30[/tex]

[tex]A_3-A_2=30[/tex]

So, this is FALSE

option-B:

[tex]A_1=\frac{1}{2}A_2[/tex]

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

[tex]A_1=\frac{1}{2}A_2[/tex]

so, this is FALSE


Answer:

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Step-by-step explanation:

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