Respuesta :
Answer:
option-B
Step-by-step explanation:
We are given
At the start of the year, 15 chameleons were introduced into a zoo
so, [tex]P_0=15[/tex]
The population of chameleons is expected to grow at a rate of 41.42% every year
so, r=0.4142
and x represents the number of years since the chameleons were introduced into the zoo
now, we can set equation to find total population
and we get
[tex]P(x)=P_0(1+r)^x[/tex]
now, we can plug values
[tex]P(x)=15(1+0.4142)^x[/tex]
[tex]P(x)=15(1.4142)^x[/tex]
Average rate of change between 2 years and 4 years:
we can use formula
[tex]A_1=\frac{P(4)-P(2)}{4-2}[/tex]
now, we can plug values
[tex]A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}[/tex]
[tex]A_1=14.99914[/tex]
Average rate of change between 4 years and 6 years:
we can use formula
[tex]A_2=\frac{P(6)-P(4)}{6-4}[/tex]
now, we can plug values
[tex]A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}[/tex]
[tex]A_2=29.99770[/tex]
Average rate of change between 6 years and 8 years:
we can use formula
[tex]A_3=\frac{P(8)-P(6)}{8-6}[/tex]
now, we can plug values
[tex]A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}[/tex]
[tex]A_3=59.99425[/tex]
now, we will check each options
option-A:
we can see that
[tex]A_3-A_2=30[/tex]
[tex]A_3-A_2=30[/tex]
So, this is FALSE
option-B:
[tex]A_1=\frac{1}{2}A_2[/tex]
So, this is TRUE
option-C:
This is FALSE
option-D:
we got
[tex]A_1=\frac{1}{2}A_2[/tex]
so, this is FALSE
Answer:
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Step-by-step explanation: