Answer: Option 'B' is correct.
Step-by-step explanation:
Let the initial concentration be
[tex]N_0=900\ g[/tex]
Let concentration after t= 90 hours be N
Since we have given that Sodium-24 has a half life of 15 hours i.e.
[tex]t_{\frac{1}{2}}=15[/tex]
So, According to question,
[tex]\text{ Number of half lives }=\frac{t}{t_{\frac{1}{2}}}\\\\\text{ Number of half lives }=\frac{90}{15}\\\\\text{ Number of half lives }=6[/tex]
As we know that
[tex]\frac{N}{N_0}=(\frac{1}{2})^n\\\\N=N_0\times (\frac{1}{2})^n\\\\N=900\times (\frac{1}{2})^6\\\\N=\frac{900}{64}\\\\N=14.0625\ g[/tex]
Hence, Option 'B' is correct.