Answer:
[tex]a=4,b=12,c=9[/tex]
Step-by-step explanation:
We must first expand, and then compare to the general quadratic form,
[tex]y=ax^2+bx+c[/tex]
The given function is
[tex]y=(2x+3)^2[/tex]
We rewrite to obtain,
[tex]y=(2x+3)(2x+3)[/tex]
This implies that,
[tex]y=2x(2x+3)+3(2x+3)[/tex]
We expand to obtain,
[tex]y=4x^2+6x+6x+9[/tex]
We simplify to get,
[tex]y=4x^2+12x+9[/tex]
Therefore the values are
[tex]a=4,b=12,c=9[/tex]
