I need help on 10 and 12. We need to put them into slope intercept form but in confused on how to do that

10) Answer: y = -3x - 7
Step-by-step explanation:
You need to use the Point-Slope formula: y - y₁ = m(x - x₁) ; where (x₁, y₁) is the point and "m" is the slope.
You are given the point (-1, -4). Now you need to find the slope.
You are given the 9x + 3y = 8. Rewrite this in slope-intercept form by solving for y so it is in the form y = mx + b.
9x + 3y = 8
-9x -9x
3y = -9x + 8
÷3 ÷3
y = -3x + 8/3
↓
m = -3
Parallel lines have the same slope so m = -3
Next, plug in the point (-1, -4) and the slope (-3) into the Point-Slope formula:
y - y₁ = m(x - x₁)
y - (-4) = -3(x - (-1))
y + 4 = -3(x + 1)
y + 4 = -3x - 3
-4 -4
y = -3x - 7
******************************************************************************************
12) Answer: [tex]y = -\frac{2}{5}x +\frac{11}{5}[/tex]
Step-by-step explanation:
follow the same steps as #10
Point (3, 1) m = ??
2x + 5y = 7
-2x -2x
5y = -2x + 7
÷5 ÷5
y = [tex]-\frac{2}{5}x +\frac{7}{5}[/tex]
↓
m = [tex]-\frac{2}{5}[/tex]
Parallel lines have the same slope so m = [tex]-\frac{2}{5}[/tex]
Next, plug in the point (3, 1) and the slope [tex](-\frac{2}{5})[/tex] into the Point-Slope formula:
y - y₁ = m(x - x₁)
y - 1 = [tex]-\frac{2}{5}[/tex](x - 3)
y - 1 = [tex]-\frac{2}{5}x[/tex]+[tex]\frac{6}{5}[/tex]
+1 +[tex]\frac{5}{5}[/tex]
y = [tex]-\frac{2}{5}x +\frac{11}{5}[/tex]