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I need help on 10 and 12. We need to put them into slope intercept form but in confused on how to do that

I need help on 10 and 12 We need to put them into slope intercept form but in confused on how to do that class=

Respuesta :

10) Answer: y = -3x - 7

Step-by-step explanation:

You need to use the Point-Slope formula: y - y₁ = m(x - x₁)  ; where (x₁, y₁) is the point and "m" is the slope.

You are given the point (-1, -4). Now you need to find the slope.

You are given the 9x + 3y = 8.  Rewrite this in slope-intercept form by solving for y so it is in the form y = mx + b.

9x + 3y = 8

-9x           -9x

       3y = -9x + 8

      ÷3    ÷3        

        y  =  -3x + 8/3

                 ↓

         m = -3

Parallel lines have the same slope so m = -3

Next, plug in the point (-1, -4) and the slope (-3) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - (-4) = -3(x - (-1))

y + 4 = -3(x + 1)

y + 4 = -3x - 3

   -4           -4  

y       = -3x - 7

******************************************************************************************

12) Answer: [tex]y = -\frac{2}{5}x +\frac{11}{5}[/tex]

Step-by-step explanation:

follow the same steps as #10

Point (3, 1) m = ??

2x + 5y = 7

-2x           -2x

        5y = -2x + 7

      ÷5    ÷5                

          y = [tex]-\frac{2}{5}x +\frac{7}{5}[/tex]

                   ↓

          m = [tex]-\frac{2}{5}[/tex]

Parallel lines have the same slope so m = [tex]-\frac{2}{5}[/tex]

Next, plug in the point (3, 1) and the slope [tex](-\frac{2}{5})[/tex] into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - 1 = [tex]-\frac{2}{5}[/tex](x - 3)

y - 1 = [tex]-\frac{2}{5}x[/tex]+[tex]\frac{6}{5}[/tex]

   +1           +[tex]\frac{5}{5}[/tex]  

y       = [tex]-\frac{2}{5}x +\frac{11}{5}[/tex]

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