Question

Your family just had a nee refrigerator delivered. The delivery man has left and you realize that the refrigerator is not quite in the right position, so you plan to move ut several netimeters. If the refrigerator has a nass of 88kg, the coefficient of kinetic friction between the bottom of the refrigerator and the floor is 0.13, and the static coefficient of friction between these same surfaces is 0.21. How hard do you have to push horizontally to get the refrigerator to start moving?

Answer 1

To get it to start moving, he have to exert a force equal to its maximum force of static friction.

F= fs,max = Ms m g= (0.21) * (180) * (9.8) = 370 N

Let me know if im wrong but if not brainliest user for helping or best answer

Answer 2

This question involves the concepts of frictional force and coefficient of friction.

The push force required to get the refrigerator to start moving is "181.3 N".

The minimum force that needs to be applied to the refrigerator in order to get it moving must be equal to the frictional force acting upon the refrigerator:

$Force = F= Frictional\ Force \\F = \mu R$

where,

F = force required to move the refrigerator = ?

μ = static coefficent of friction = 0.21

R = normal reaction of surface = weight of refrigerator = mg

m = mass of refrigerator = 88 kg

g = acceleration due to gravity = 9.81 m/s²

Therefore,

$F = \mu mg\\F = (0.21)(88\ kg)(9.81\ m/s^2)$

F = 181.3 N

Learn more about frictional force here:

https://brainly.com/question/1714663?referrer=searchResults

The attached picture shows frictional force.