Question

what is the molarity of 416.48 g BaCl2 dissolved in 2 L of water? Please help!!!

A) 1 M
B) 104.12 M
C) 2 M
D) 208.24 M

Answer 1

The answer should be A 1M

Answer 2

Answer:

The correct answer is option A.

Explanation:

Molarity is defined as the number of moles that are present in one liter of solution.

Mathematically,

$\text{Molarity of the solution}(M)=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Mass of barium chloride = 416.48 g

Moles of barium chloride = $\frac{ 416.48 g}{208.23 g/mol}=2.000 mol$

Molarity of solution = M = ?

Volume of solution = 2 L

Putting values in above equation, we get:

$M=\frac{2.000 mol}{2 L}= 1 mol/L = 1 M$

1 M is the molarity of 416.48 grams barium chloride dissolved in 2 liter of water.