Question

Apply the Pythagorean Theorem to find the distance between points A and C.

Answer 1

the horizontal distance ( x direction) from A to C is 7 units and

the vertical distance ( y direction) is 5 units

Applying Pythagoras' Theorem to the right triangle

AC² = 7² + 5² = 49 + 25 = 74, hence

AC = $\sqrt{74}$ = 8.6 units ( to 1 dec. place )

Answer 2

Hi!

distance from A to the base od C, straight line = 7 units

from the base of C to the point C, straght line = 5 units

$AC^{2} = 7^{2} + 5^{2} \\AC^{2} = 49 + 25\\AC^{2} = 74\\AC = \sqrt{74}\\AC = 8,6$

Hope this helps!