Answer:
0.012
Step-by-step explanation:
Linear approximation says that,
[tex]f(x) \approx f(x_o)+f'(x_o)(x-x_o)[/tex]
For a cube the surface area is [tex]6x^2[/tex].
So the side is 1.0 inch in, the surface area is [tex]=6\times1^2 = 6[/tex] square inches.
In Linear approximation means you ignore the term [tex]x_o^2[/tex] , if [tex]x_o[/tex] is a small number, because then [tex]x_o^2[/tex] will be a very smalle number and that does not contribute much to the error.
So the surface area is approximately,
[tex]6x^2=6x_o^2+12x_o(x-x_o)[/tex]
So here, [tex]x=1.001, x_o=0.001[/tex]
The error in the area is approximately,
[tex]12 \times 0.001=0.012[/tex]
So the error is 0.012.