Respuesta :

Answer

B)[tex](x-5)^{2} + y^{2} = 9[/tex]


Step by step explanation

The standard form of circle when center(h, k) and radius r, given is

(x - h)^2 + (y - k)^2 = r^2

Given: (h, k) = (5, 0) and r = 3

Now plug in these values in the standard form, we get

(x - 5)^2 + (y - 0)^2 = 3^2

[tex](x- 5)^{2} + y^{2} = 9[/tex]

Therefore, the answer is B) [tex](x-5)^{2}  + y^{2} = 9[/tex]

Thank you :)

B. it is (x-5)^2+y^2=9
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