graph y=-1/4x+5 how do you graph this?
![graph y14x5 how do you graph this class=](https://us-static.z-dn.net/files/d29/d9c2ba8e1a73b90bca4d44bbb03a990a.jpg)
Hey there!!
The given equation is slope-intercept form.
... y = mx + b. In this equation, the 'b' is the y-intercept and the m i the slope.
Given:
... y = -1/4x + 5
First, we will have to place the point at ( 0,5 ) as the y-intercept is 5.
Now, taking the (0,5) as the start, we will have to place the other point after moving down one unit and 4 across as the slope is -1/4.
Hence, the two points we will get doing this are (0,5) and (4,4)
Now, we will need to connect these two points and draw arrow at the end.
We now have a line!
Hope my answer helps!
Happy Thanksgiving! :)
It is a linear function. The graph is a straight line.
We need only two points to plot a graph of a linear function.
Select two any x values and calculate the y values:
[tex]y=-\dfrac{1}{4}x+5\\\\for\ x=0\to y=-\dfrac{1}{4}(0)+5=0+5=5\to(0,\ 5)\\\\for\ x=4\to y=-\dfrac{1}{4}(4)+5=-1+5=4\to(4,\ 4)[/tex]