Question

A bowl contained 13 red and brown M&M's. there was one more red m&m than brown m&m. How many of each color are in the bowl ?

Answer 1

7 red M&M's and 6 brown M&M's.

Answer 2

Answer:

6 brown m&m.

7 red m&m.

Step-by-step explanation:

Let B represent brown M&M's and R represent red M&M's.

We have been given that a bowl contained 13 red and brown M&M's. We can represent this information in an equation as:

$B+R=13...(1)$

We are also told that there was one more red m&m than brown m&m. We can represent this information in an equation as:

$R=B+1...(2)$

Upon substituting equation (2) in equation (1), we will get:

$B+B+1=13$

$2B+1=13$

$2B+1-1=13-1$

$2B=12$

$\frac{2B}{2}=\frac{12}{2}$

$B=6$

Therefore, there are 6 brown m&m.

Upon substituting $B=6$ in equation (2), we will get:

$R=B+1$

$R=6+1$

$R=7$

Therefore, there are 7 red m&m.