The point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
We have the point [tex](-8,\ 2)[/tex] and the slope [tex]m=\dfrac{1}{2}[/tex].
Substitute:
[tex]y-2=\dfrac{1}{2}(x-(-8))\\\\\boxed{y-2=\dfrac{1}{2}(x+8)}[/tex]