Question

What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?What are the solutions of this equation? 47 m 2 + 88 m + 39 = 0

Answer 1

x= 5+√31/2, 5-√31/2

and

m= -44±√103/47

m≈ -0.72023634, -1.15210407

Answer 2

Answer:

Hi!

For f(x) = 2x^2 – 10x – 3, the zeros for this quadratic are:

• $x_1 = -\frac{5}{2} + \frac{\sqrt{31}}{2} \approx 5.28$

• $x_2 = \frac{5}{2} - \frac{\sqrt{31}}{2} \approx -0.28$

For f(m) = 47m^2 – 88m + 33 = 0, the solutions for this equation are:

• $m_1 = -\frac{44}{47} - \frac{\sqrt{103}}{47} \approx -1.15$

• $m_2 = -\frac{44}{47} + \frac{\sqrt{103}}{47} \approx -0.72$

Step-by-step explanation:

Having a quadratic function: ax^2 + bx + c = 0, the values of x which are the solutions of the equation are given by the quadratic formula.

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